Let f (x)=6x^3-7x^2-9x-2 and substitute these values to x and you will find f (2)=0. This means that x=2 is one of the roots and thus f (x) is divisivle by (x-2).

f (x) has zeros +-sqrt (5) and -2 Given: f (x) = 3x^3+6x^2-15x-30 Note that all of the terms are divisible by 3. In addition, the ratio of the first and second terms is the same as that of the third and fourth terms.

Let "mass of X" = x and "mass of O" = y. y/ (x + y) = 0.6 y = 0.6x + 0.6y 0.4y = 0.6x y = (0.6x)/0.4 = 1.5x Let "mass of x = 32 u". Then "mass of O = 1.5 × 32 u = 48 u". ulbb ("Element"color (white) …

Jan 29, 2017 · 6x^2+x-1 = (2x+1) (3x-1) Here are a couple of methods (in no particular order): Method 1 Note that: (ax+1) (bx-1) = abx^2+ (b-a)x-1 Comparing with: 6x^2+x-1 we want to find a, b such that …

Measure of angle LhatOM = 48^0 7x-92+6x+12=180 1) Combine like terms 7x - 92 + 6x + 12 =180 13x - 80= 180 2) Add color (blue) (80) to both sides (13x) - cancel80 color (blue) (+ cancel80) = 180 color …

0, 1, 3 To solve this, we set the equation equal to 0 and factor it. First, we can factor out 6x to get 6x(x^2-4x+3)=0. Next we can factor out the area in parentheses. To do this, we need to find two …

How do you use the important points to sketch the graph of y = x2 − 6x + 1? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs

We're dividing a single term, #6x^3#, into a polynomial, so we can take advantage of the following fact which allows us to effectively divide one term into other terms:

x=9 So we have: x-1=sqrt (6x+10) Let's try to remove the square root sign. We square both sides. (x-1)^2= (sqrt (6x+10))^2 x^2-2x+1=6x+10 We see that we can form a quadratic equation. =>x^2-8x …

May 19, 2018 · 59 degrees Since ABCD is a cyclic quadrilateral, then angle ABC + angle ADC = 180 (opposite angles in cyclic quadrilateral are equal to 180 degrees) 2x+3+4x+3=180 6x ...